MATH SOLVE

4 months ago

Q:
# Rolling a Red and Yellow Dice(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)A red die and a yellow die are rolled. The outcome "3 on the red die and 4 on the yellow die" can be represented by the ordered pair (3,4). What is the probability that the yellow dice has a larger value than the red dice? 7 / 181 / 25 / 121 / 6

Accepted Solution

A:

Answer:Option C 5/12 is correct optionStep-by-step explanation:We have to find the probability that shows yellow dice has a larger value than the red dice.Probability= total no of favorable outcomes / total no of outcomesin our case, considering the data set, we have to find those pair where value of yellow die is greater than the red die. Where (1,2) represents 1 on the red die and 2 on the yellow die (1,2) (1,3) (1,4) (1,5) (1,6)
(2,3) (2,4) (2,5) (2,6)
(3,4) (3,5) (3,6)
(4,5) (4,6)
(5,6)
These are the possibilities where yellow die has greater value than red die.total no of favorable outcomes = 15total no of outcomes = 36probability that yellow die has greater value than red die = 15 / 36 = 5/ 12Option C 5/12 is correct option